Solution

ID: past-exam-of-the-options-ii-course-of-the-university-of-oxford/2009/a/a2/iii/solution

Here the iteration index is a positive integer: . If , then fixes and the generator, so it fixes all of . Every element of would then solve . A nonzero polynomial of degree over a field has at most roots, contradicting . Thus . The printed inequality alone omits positivity of ; at the claimed inequality would be false.

New to topics? Read the docs here!