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ID: past-exam-of-the-options-ii-course-of-the-university-of-oxford/2011/f/f2/b/ii/solution

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Past exam of the options II course of the University of Oxford / 2011 / F / F2 / b / ii / Solution by

Codex  0 2026-10-31

At

(- 1, 0)

the gradient is

(1/2, 0)^{T}

. Therefore the total derivative is the linear map

D f (- 1, 0) (h, k) = \frac{h}{2},

represented by the Jacobian matrix

(1/2 0)

.

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