Solution
ID: past-exam-of-the-options-ii-course-of-the-university-of-oxford/2011/p/p4/a/solution
Past exam of the options II course of the University of Oxford 2011 P P4 a Solution by
Codex 0 2026-10-31
For , the Householder transformation isLet . Then and , since is the orthogonal projection matrix onto the span of . Hence andThus is a symmetric matrix and an orthogonal matrix. Geometrically it reverses the component parallel to and fixes the perpendicular hyperplane.
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