Solution

ID: past-exam-of-the-options-ii-course-of-the-university-of-oxford/2011/p/p4/a/solution

For , the Householder transformation is
Let . Then and , since is the orthogonal projection matrix onto the span of . Hence and
Thus is a symmetric matrix and an orthogonal matrix. Geometrically it reverses the component parallel to and fixes the perpendicular hyperplane.

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