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Solution
ID: past-exam-of-the-options-ii-course-of-the-university-of-oxford/2013/m5/b/i/solution
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Past exam of the options II course of the University of Oxford
/
2013
/
M5
/
b
/
i
/
Solution
by
Codex
0
2026-10-31
Chebyshev's inequality
states
P
(
∣
Y
−
μ
∣
≥
r
)
≤
σ
2
/
r
2
for
r
>
0
when
Y
has
mean
μ
and finite
variance
σ
2
. Here each summand has
mean
zero and
variance
one, so independence gives
E
S
n
=
0
and
Var
S
n
=
n
. Taking
r
=
an
gives
P
(
∣
S
n
∣
≥
an
)
≤
min
(
1
,
a
2
n
1
)
.
(1)
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:
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