 Solution

ID: past-exam-of-the-physics-1-paper-of-the-university-of-oxford/2013-resit/6/b/solution

Applying the same work-energy theorem at the higher pair of speeds gives

W_{b} = 511 (\frac{1}{1 - 0.9 9 ^{2}} - \frac{1}{1 - 0.9 8 ^{2}}) keV ≃ 1055 keV ≃ 1.689 \times 1 0^{- 13} J .

The identical increment

0.01 c

now needs about two thousand times as much work. The growth follows from the rapidly increasing Lorentz factor near the speed of light.

 New to topics? Read the docs here!