 Solution

After the electric field is removed, the uniform magnetic field preserves the speed. Decompose the instantaneous initial velocity as ${\mathbf{v}}_0={\mathbf{v}}_{\parallel }+{\mathbf{v}}_{\perp }$, with $\hat{\mathbf{b}}=\mathbf{B}/B$ and signed $\Omega =qB/m$. Thenand, integrating,This is a helical motion in a uniform magnetic field of radius $m|{\mathbf{v}}_{\perp }|/(|q|B)$ and angular frequency $|q|B/m$. It is a circle if ${\mathbf{v}}_{\parallel }=0$, and a straight line if ${\mathbf{v}}_{\perp }=0$. The formula assumes a uniform, nonzero field and nonrelativistic motion.