 Solution

For each primitive linear, square or cubic Bravais lattice of spacing $a$, the reciprocal lattice has spacing $2\pi /a$. The first Brillouin zone is consequently the interval, square or cube with faces at components $k_i=\pm \pi /a$. The nearest zone boundary is a distance $k_B=\pi /a$ from the centre. The ratios areAll are below one: the ideal free-electron Fermi surface lies wholly inside the first Brillouin zone. Its nearest approach to the boundary is in three dimensions, where it lies only about $1.53\%$ short of the nearest face. A lattice-induced band gap at a zone face therefore does not by itself make these half-filled systems insulating in the stated free-electron model. Interactions, structural changes and actual electronic band structure can alter that model prediction.