 Solution

ID: past-exam-of-the-physics-course-of-the-year-1-of-the-natural-sciences-course-of-the-university-of-cambridge/2024/paper-1/section-b/7/c/solution

For the lander,

u / c = 35/37

, so

γ_{u} = \frac{1}{1 - ( 35/37 ) ^{2}} = \frac{37}{12} .

K = (γ_{u} - 1) m c^{2} = \frac{25}{12} (4 \times 1 0^{5}) c^{2} = 7.49 \times 1 0^{22} J .

m c^{2}

is excluded from kinetic energy.

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