Solution

ID: past-exam-of-the-probability-course-of-the-university-of-oxford/2015/2/b/ii/solution

Integrating the joint probability density across gives the marginal density
For every , the conditional probability density is consequently
Hence
This also follows from two independent exponential variables conditioned on their sum: given , the variable is uniform on , and . Conditioning on here is defined through the conditional probability density, rather than division by , which is zero. The endpoint lies outside the positive marginal support and needs no specified conditional law.

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