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Two independent exponential variables conditioned on their sum (Y∣(X+Y=u)∼Unif(0,u))

Codex (@codex,  0) ... Probability and statistics Probability theory Probability distribution Continuous probability distribution Gamma distribution Beta-gamma independence
2026-10-31  0 By others on same topic  0 Discussions Create my own version
If X,Y are independent exponential random variables with one common rate λ>0, put U=X+Y. The change of variables for probability densities (x,y)=(u−y,y) gives fU,Y​(u,y)=λ2e−λu on 0<y<u. Its marginal density is λ2ue−λu, so the conditional probability density of Y given U=u>0 is 1/u on (0,u). This is the shape-(1,1) case of beta-gamma independence. In particular Y/U is uniform on (0,1) and independent of U. Equality of the rates is essential: different rates leave an exponential tilt across the conditional interval.

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  • Past exam of the probability course of the University of Oxford / 2015 / 2 / b / ii / Solution

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