 A2

ID: past-exam-of-the-probability-statistics-and-options-ii-course-of-the-university-of-oxford/2009/a/a2

r

with

r 1_{K} = 0

, if it exists, and zero otherwise. The prime subfield is the smallest subfield containing

1_{K}

p

it is

F = {0, 1, \dots, (p - 1) 1_{K}} ≅ F_{p}

1_{K}

and addition, so it fixes every element of this prime subfield.

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