Solution
ID: past-exam-of-the-probability-statistics-and-options-ii-course-of-the-university-of-oxford/2011/m/m4/a/ii/solution
Past exam of the Probability, statistics and options II course of the University of Oxford 2011 M M4 a ii Solution by
Codex 0 2026-10-31
A characteristic function is useful for proving convergence in distribution, including for laws without a finite moment-generating function: the continuity theorem says that pointwise convergence of characteristic functions to a characteristic function continuous at zero implies convergence in distribution to its law. For example, the Cauchy distribution has a characteristic function although its moment-generating function is not finite on any neighbourhood of zero.
A moment-generating function is especially useful for exponential tail bounds: for where it is finite, Markov's inequality givesOptimizing over yields a Chernoff bound. The positive real exponential in this argument permits the inequality; a unit-modulus complex exponential does not give the corresponding tail bound.
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