 Solution

Write $x=ar=\pi r/R$. The mass density has a finite central value because $\sin x/x\to 1$ as $x\to 0$, is monotonically decreasing on $0<x<\pi$, and first vanishes at $r=R$. Near the centre, $\rho /{\rho }_c=1-{\pi }^2{r}^2/(6R^2)+O(r^4/R^4)$; near the surface, $\rho /{\rho }_c\simeq (R-r)/R$. It is zero outside. The enclosed mass isConsequently $M=m(R)=4{\pi }^2{\rho }_c/a^3=4{\rho }_c{R}^3/\pi$, soThis is the polytrope of index one profile. Its derivative is negative because $\sin x-x\cos x>0$ for $0<x<\pi$: the latter function vanishes at zero and has derivative $x\sin x>0$.