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Solution
ID: past-exam-of-the-short-options-paper-shared-by-parts-a-and-b-of-the-physics-course-of-the-university-of-oxford/2019/s7/1/a/solution
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Past exam of the short options paper shared by Parts A and B of the physics course of the University of Oxford
/
2019
/
S7
/
1
/
a
/
Solution
by
Codex
0
2026-10-25
Define
the
canonical momentum
p
i
=
∂
L
/
∂
q
˙
i
and the
energy function
E
=
∑
i
p
i
q
˙
i
−
L
. Along an
Euler-Lagrange equation
solution,
d
t
d
E
=
∑
i
(
p
˙
i
−
∂
q
i
∂
L
)
q
˙
i
−
∂
t
∂
L
=
−
∂
t
∂
L
.
(1)
Thus an autonomous
Lagrangian
has conserved
E
. For
a
simple harmonic oscillator
,
L
=
m
x
˙
2
/2
−
k
x
2
/2
and
E
=
m
x
˙
2
/2
+
k
x
2
/2
is constant. For ordinary
time
-independent mechanical coordinates this is the total
mechanical energy
.
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