 Solution

Choose complex amplitudes proportional to $e^{i\omega t}$ and define $\tilde{\sigma }=G^{\ast }(\omega )\widetilde{ϵ}$. The Maxwell model givesRationalizing the denominator yields the storage modulus and loss modulus:For $\omega \tau \ll 1$, $G^{\prime \prime }\simeq \eta \omega$ dominates and $G^{\prime }\simeq G_0{\omega }^2{\tau }^2$ is small: the material has time to flow. For $\omega \tau \gg 1$, $G^{\prime }\to G_0$ and $G^{\prime \prime }\simeq G_0/(\omega \tau )$: the dashpot scarcely deforms during a cycle and the response is mainly elastic. At $\omega \tau =1$, $G^{\prime }=G^{\prime \prime }=G_0/2$, and $G^{\prime \prime }$ is maximal. The stress leads strain by $\delta =\arctan (G^{\prime \prime }/G^{\prime })$, ranging from nearly $\pi /2$ to nearly zero.

For a fixed strain amplitude ${ϵ}_a$, dissipation per cycle is $\pi G^{\prime \prime }{ϵ}_a^2$. A peak in $G^{\prime \prime }$ therefore concerns that normalization. At fixed stress amplitude ${\sigma }_a$, it is instead $\pi {\sigma }_a^2/(\eta \omega )$, so it has no finite-frequency maximum in this ideal model. Reversing the Fourier time convention reverses the imaginary-part sign, while the physical dissipated energy remains positive.