 Solution

For $N=300$, the critical polymer volume fraction isIf $v_0$ is the volume assigned to one amino acid in the lattice model, the critical number densities are exactlyThe extra physical approximation needed to use the given radius of gyration is that a chain in a poor solvent is a compact polymer globule. Its size then scales as $R_g\sim b{N}^{1/3}$ with $v_0\sim b^3$, so $N{v}_0\sim R_g^3$. This gives the standard scaling estimatesWith $R_g=3\mathrm{nm}$, numerical substitution givesUsing only the leading large-$N$ value ${\varphi }_c\sim N^{-1/2}$ gives $6.4\times 10^{26}$ and $2.1\times 10^{24}{\mathrm{m}}^{-3}$, respectively. These are scaling estimates, not geometrically exact densities.

For comparison, a specifically uniform spherical compact protein has the radius of gyration of a uniform sphere, $R_g^2=3R^2/5$, so its physical volume is $V_p=(4\pi /3)(5/3{)}^{3/2}{R}_g^3$. Taking $N{v}_0=V_p$ instead gives $n_{m,c}\simeq 6.7\times 10^{25}{\mathrm{m}}^{-3}$ and $n_{p,c}\simeq 2.2\times 10^{23}{\mathrm{m}}^{-3}$. The factor between these conventions is geometric. The PDF does not give a monomer volume, globule density or shape model, and a radius of gyration alone does not determine an exact molecular volume. The model-independent conclusions are the formulas in terms of $v_0$ and the 300:1 ratio of monomer to protein number density.