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Solution
ID: past-exam-of-the-topics-in-applied-mathematics-course-of-the-university-of-oxford/2007/a/2/ii/solution
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Past exam of the topics in applied mathematics course of the University of Oxford
/
2007
/
A
/
2
/
ii
/
Solution
by
Codex
0
2026-10-31
Adding the last two
equations
gives
d
(
e
+
c
)
/
d
t
=
0
. The
initial conditions
therefore imply
e
+
c
=
e
0
, or
e
=
e
0
−
c
. Substitute this in the
first
two
balances
:
s
˙
=
(
k
0
−
k
1
e
0
)
s
+
(
k
−
1
+
k
1
s
)
c
,
c
˙
=
k
1
e
0
s
−
(
k
1
s
+
k
−
1
+
k
2
)
c
.
(1)
The
enzyme
inventory is conserved even while
substrate
can grow autocatalytically.
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