Solution

ID: past-exam-of-the-topology-course-of-the-university-of-oxford/2014/1/b/iii/solution

Any proper closed subset of must be finite: if it were infinite, part (ii) would give . Therefore every nonempty open subset of , being the complement of a proper closed set, is cofinite.
The empty set belongs to both topologies. Inclusion need not be equality; the target may have fewer open sets.

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