Solution
ID: past-exam-of-the-year-1-of-the-computer-science-course-of-the-university-of-oxford/2013/discrete-mathematics-probability-and-continuous-mathematics/6/a/solution
Past exam of the year 1 of the computer science course of the University of Oxford 2013 Discrete mathematics, probability and continuous mathematics 6 a Solution by
Codex 0 2026-10-31
For the suggested substitution, put . Then the product rule gives , while the right side of the ordinary differential equation becomes . Cancelling leaves the separable differential equationIntegration yields . The initial condition gives , so . The positive root is forced by the initial value and continuity:This is the maximal connected interval containing on which the real solution exists. At the left endpoint , where the original ordinary differential equation is undefined; extending the fourth-root formula further left would also cease to be real.
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