 Solution

ID: past-exam-of-the-year-1-of-the-computer-science-course-of-the-university-of-oxford/2017/discrete-mathematics-continuous-mathematics-and-probability/6/c/i/solution

x_{n + 1} = x_{n} + h, y_{n + 1} = y_{n} + h f (x_{n}, y_{n}) .

Here

x_{n} = x_{0} + nh

and the initial approximation normally equals the given initial value. Each step takes a tangent-line increment of width

h

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