 Solution

The first column has norm two, giving $q_1=(1,-1,1,-1{)}^T/2$. Its inner products with the second and third columns are both one. Subtracting $q_1$ from the second column leaves $(3,3,3,3{)}^T/2$, of norm three, so $q_2=(1,1,1,1{)}^T/2$. The inner product of $q_2$ with the third column is one. Subtracting $q_1+q_2$ from that column leaves $(1,1,-1,-1{)}^T$, of norm two. Thus the Gram-Schmidt process givesThe columns of $Q$ have unit norm and pairwise zero inner products, so $Q^{T}Q=I_3$. Direct multiplication verifies $QR=A$.