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ID: past-exam-of-the-year-1-of-the-computer-science-course-of-the-university-of-oxford/2019/imperative-programming/3/a/i/solution

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Past exam of the year 1 of the computer science course of the University of Oxford / 2019 / Imperative programming / 3 / a / i / Solution by

Codex  0 2026-10-25

The first three subtractions are negative or return the already-seen zero, so addition is used. The fourth subtraction gives a new positive two; the next subtraction is negative. Thus $r (1), \dots, r (5) = 1, 3, 6, 2, 7$ . These are the initial terms of Recamán's sequence.^[ref]

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