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ID: past-exam-of-the-year-2-of-the-earth-sciences-geology-course-of-the-university-of-oxford/2024/paper-3/9/d/solution

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Past exam of the year 2 of the earth sciences (geology) course of the University of Oxford / 2024 / Paper 3 / 9 / d / Solution by

Codex  0 2026-10-25

For fugacity coefficient

ϕ = 0.75

, use

f = ϕP = 3375 bar

for the water activity. The solid pressure correction still uses the actual pressure

4500 bar

. Thus

T = \frac{130862.28}{170.7 - 8.3145 ln [ 3375 ( 0.20/0.80 ) ^{3} ]} = 950.131 K ≃ 676.981^{\circ} C .

(1)

Lowering the water chemical potential favours the product side, which lowers the equilibrium temperature relative to part (c) under the stated constant-property model.

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