 Soft-photon resonant capture threshold

In energy units $m=m_{\mathrm{in}}{c}^2$ and $M=M_A{c}^2$, capture of a photon of energy $e$ by a massive particle into one resonance satisfies $E-P\cos \theta =(M^2-m^2)/(2e)=2E_0$, with $P=pc$. Head-on incidence gives the largest invariant mass at fixed $E$, so the threshold solves $E+P=2E_0$. Using $E^2-P^2=m^2$ gives the title expression. It is the minimum over incident angle; above that energy the exact angle is fixed by the invariant equation, not arbitrary. The soft-photon regime $2E_0\gg m$ excludes exactly co-propagating incidence.