 Stability of a cubic-quartic scalar potential

For $V(\varphi )=m^2{\varphi }^2/2-\mu {\varphi }^3/6+\lambda {\varphi }^4/24$, positive $\lambda$ makes the classical potential bounded below. For $m^2\ge 0$, completing the square givesThus zero is a global minimum precisely when ${\mu }^2\le 3\lambda m^2$. At a nontrivial equality there are degenerate minima at zero and $2\mu /\lambda$. If $m^2>0$ and the inequality fails, zero is a false vacuum: its Hessian is positive but another minimum has lower energy. A negative quartic coupling, or a nonzero cubic term without a quartic term, is unbounded below. These are classical or tree-level criteria.