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Computational complexity of modular exponentiation

Ciro Santilli (@cirosantilli, 37) Mathematics Area of mathematics Number theory Modular arithmetic Modular exponentiation
Updated 2025-07-16  0 By others on same topic  0 Discussions Create my own version
math.stackexchange.com/questions/2382011/computational-complexity-of-modular-exponentiation-from-rosens-discrete-mathem mentions:
bnmodm
(1)
can be calculated in:
log(m)2log(n)
(2)
Remember that log(m) and log(n) are the lengths in bits of m and n, so in terms of the length in bits M and N we'd get:
M2N
(3)

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