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Put $K=nY$. Apart from a factor independent of $p$, the likelihood isThus the score function and Fisher information matrix are

The Newton method and Fisher scoring updates are respectivelySince $\hat{p}=Y$, initialization at $p^{(0)}=Y$ requires zero steps for either algorithm. Moreover,so binomial-proportion Fisher scoring reaches the MLE in one step from every interior $p^{(0)}\ne Y$.

The incompressible Stokes equations areTaking the curl gives ${\nabla }^2\omega =0$. For a planar stream function, $\omega =-{\nabla }^2\psi$, so the biharmonic stream function for planar Stokes flow satisfies

For $\psi =r^{2}f(\theta )$,The polar rate-of-strain components areHence

Sincebiharmonicity givesNo slip at $\theta =-\alpha$, no penetration at $\theta =0$, and the imposed tangential traction givePut $\Delta =\sin 2\alpha -2\alpha \cos 2\alpha$. Solving,The upper-surface velocity is radial and equals $r{f}^{\prime }(0)$. Therefore the similarity solution for tangentially forced Stokes wedge gives