An abelian group presentation specifies generators of a group and additive relations. For generators , let be the subgroup of generated by the relation vectors; the presented abelian group is . The orders of the images of the generators can be smaller than the orders imposed by individual relations. A relation only requires that the order of a group element divide .
The exact orders printed in the question are inconsistent. The source PDF says that the orders of group elements are , respectively, and also imposes . Multiplying this relation by and using gives . Since also holds, subtracting gives , contradicting the stated order of a group element . Thus
The natural abelian group presentation interpretation is to impose the relations and , with no further relations, without requiring the orders of the images of the generators to stay . Under this interpretation the calculation is as follows. Since follows from , the mixed relation gives . Consequently , and together with this gives . Conversely, , , and imply every original relation. Eliminating leaves two independent cyclic groups:
To verify that these relations force no further identifications, map to in . All defining relations hold, and the inverse group homomorphism sends the two standard generators to . These group homomorphisms are mutually inverse. The divisibility condition gives the requested invariant factors of a finitely generated module over . In this presented group, actually have orders .
Equivalently, the relation matrix
has nonzero Smith normal form entries , with the trivial factor omitted. The displayed direct sum of modules is the answer to the presentation interpretation; the inconsistency of the literal exact-order formulation remains.