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{title2=$\alpha(\mathbf k_1,\mathbf k_2)$}

The continuity-equation kernel is
$$
\alpha(\mathbf k_1,\mathbf k_2)
=\frac{(\mathbf k_1+\mathbf k_2)\mathbin\cdot\mathbf k_1}{k_1^2}.
$$
Its symmetrization is $\alpha_s=1+(\mathbf k_1\mathbin\cdot\mathbf k_2)(k_1^{-2}+k_2^{-2})/2$.


Alpha mode-coupling kernel

Past exam of the mathematics course of the University of Cambridge / 2026 / iii / Paper 312 / 2 / i / Solution

Alpha mode-coupling kernel ( $α (k_{1}, k_{2})$ )

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Alpha mode-coupling kernel (α(k1​,k2​))

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