Write . The mean-field approximation drops the quadratic product of the fluctuations:
For a Hermitian pairing interaction, the two linear terms are Hermitian conjugates. Defining the BCS anomalous average and pairing field by , and writing , gives
The final constant corrects the double counting in the reduced BCS pairing Hamiltonian.
In each factor of the BCS ground state, the BCS anomalous average is . Self-consistency therefore gives the zero-temperature BCS gap equation
Put . The specified constant attractive interaction makes independent of inside the energy shell and zero outside it:
The printed is incompatible with this interaction: labels relative pair momentum, not the total momentum of a Cooper pair. Every pair here has zero total momentum, while many relative momenta contribute.
For the nonzero solution, the constant-shell BCS gap equation becomes . Let denote the approximately constant single-spin density of states per unit volume at the Fermi level. Then
In weak coupling, . The displayed answer in the question uses . If “total electronic density of states” includes both spin species, , the argument instead reads . If the density counts the whole box rather than unit volume, divide it by before using this formula.
The reduced BCS pairing Hamiltonian retains scattering of opposite-momentum, opposite-spin Cooper pairs:
A mean-field approximation introduces the BCS anomalous average and pairing field . The subtraction corrects the double counting of the mean-field interaction energy.