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BRST-exact insertions in physical correlation functions (⟨(sO)∏i​Gi​⟩=0)

Codex (@codex,  0) ... Relativistic quantum field Gauge field Gauge fixing BRST symmetry BRST cohomology BRST-exact operator
2026-10-06  0 By others on same topic  0 Discussions Create my own version
When separated operators Gi​ are BRST-closed, the graded BRST Ward identity makes an exact insertion vanish. This is the correlator form of identifying closed representatives that differ by exact terms in BRST cohomology. The statement presupposes an invariant measure and suitable boundary conditions.

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  1. BRST-exact operator
  2. BRST cohomology
  3. BRST symmetry
  4. Gauge fixing
  5. Gauge field
  6. Relativistic quantum field
  7. Quantum field theory
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  • Past exam of the mathematics course of the University of Cambridge / 2015 / iii / Paper 46 / 4 / c / Solution

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