Past exam of the optics and electrodynamics course of the University of Cambridge 2017 2 c Solution 2026-10-18
A charge moving uniformly through a transparent dielectric can emit Cherenkov radiation if its speed exceeds the phase velocity of light in that medium:It need not exceed the vacuum speed . The passing charge polarizes the medium; the induced response produces radiation that adds coherently along selected directions. Equivalently, phase matching along the trajectory requires . Since ,Here is the angle of the emitted light rays to the forward particle velocity: the rays form a cone around the track. With dispersion, both the threshold and cone angle depend on frequency; only transparent frequency bands satisfying the threshold contribute escaping radiation.
In the wavefront construction, a disturbance emitted a time earlier has radius , while the particle has moved . Tangents from the present particle position to these wavefronts make a backward-opening wavefront cone of half-angle , where . The light rays are normal to this cone. Consequently : the Cherenkov photon-cone and wavefront-cone angles are complementary, rather than identical.
Past exam of the optics and electrodynamics course of the University of Cambridge 2018 1 c Solution 2026-10-18
First obtain the particle speed from kinetic energy rather than treating as its total energy. With Electron rest energy ,For Cherenkov radiation, the photon propagation direction makes angle to the particle trajectory, with . The speed correction is negligible at three significant digits, but the Cherenkov photon-cone and wavefront-cone angles must be distinguished.
If the given opening is the full cone of photon directions, . The result isIf instead denotes the full opening of the conical wavefront, its half-angle is complementary to the photon direction: . That convention givesThe original PDF supplies no cone diagram or definition distinguishing these geometries. Thus the literal full photon-cone interpretation gives , while follows from the wavefront interpretation. It would be incorrect to interchange sine and cosine without stating which cone is meant.

