Past exam of the mathematics course of the University of Cambridge 2005 iii Paper 21 4 a Solution Created 2026-10-03 Updated 2026-10-14
Fix a finite-rank free abelian group . A pure integral Hodge structure of weight is a decompositionIts Hodge numbers are , and its Hodge filtration is . Equivalently, the filtration has these dimensions and satisfiesThe decomposition is recovered as .
A polarized Hodge structure additionally has a nondegenerate integral bilinear form satisfying , extended complex-bilinearly, withWe choose the geometric sign convention in which the positivity condition isThe expression is real by the symmetry and conjugation conditions. In particular it is on a weight-one summand. Other conventions absorb the constant factor into ; a consistent choice matters in weight two.
Fix , and the Hodge numbers. The compact dual of a period domain is the projective flag varietyThe orthogonality conditions are algebraic. The Griffiths domain is the subset whose filtrations also satisfy real opposition and the displayed positivity. It is open in the usual complex topology of ; the inequalities are not additional complex algebraic equations. Thus retains the complex flag conditions, whereas retains genuine polarized Hodge structures.
Period domain 2026-10-14
Fix a lattice, a bilinear polarization and Hodge numbers. The period domain consists of the Hodge filtrations with these dimensions satisfying orthogonality, opposition and positivity. It is an open subset of its compact dual of a period domain, described algebraically by the dimensions and orthogonality conditions alone.