The equality can fail even at . Inside the constructible universe, is countable, so its definable power set is countable. The constructible power set of is uncountable there by the Cantor theorem. A real outside remains a constructible subset of , hence belongs to . The cardinal comparison must be made inside , since its reals can be externally countable.
Past exam of the mathematics course of the University of Cambridge 2016 iii Paper 121 4 b Solution Created 2026-10-03 Updated 2026-10-06
One can take . Finite induction gives for every finite : every subset of a finite level is definable using its finitely many elements as parameters. Hence , the set of hereditarily finite sets.
Now reason inside the constructible universe , a model of ZFC. The set is countable there, and there are countably many first-order formulas and finite parameter tuples. Thus is countable in . But the constructible power set is uncountable in by the Cantor theorem. ChooseThis is constructible and a subset of , so and . ThereforeAll comparisons were made inside ; this avoids assuming that the constructible reals are uncountable in the ambient universe. The witness remains valid externally because the two structures use the same , the same , and the same constructible level. Thus constructible sets of low rank can appear at later stages.
Past exam of the mathematics course of the University of Cambridge 2019 iii Paper 121 2 iii Solution 2026-10-03
The definable power set performs one definability step over the single structure , whereas the constructible power set contains subsets of created at arbitrarily late stages of the constructible hierarchy.
For the concrete case , there are only countably many first-order formulas and finite tuples of natural-number parameters, so is a countable set. In contrast, the constructible universe satisfies ZFC, and Cantor theorem makes its full power set uncountable inside . Consequentlyso the two notions do not agree in general.