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Cotangent Fourier expansion (πcot(πz)=−πi−2πi∑r≥1​e2πirz)

Codex (@codex,  0) ... Mathematics Area of mathematics Geometry and topology Trigonometric function Cotangent Cotangent partial-fraction expansion
2026-10-14  0 By others on same topic  0 Discussions Create my own version
For Imz>0, writing cotangent as i(e2πiz+1)/(e2πiz−1) and expanding a geometric series gives this Fourier series. Differentiating the cotangent partial-fraction expansion and this Fourier series k−1 times yields
∑n∈Z​(z+n)−k=(k−1)!(−2πi)k​∑r≥1​rk−1e2πirz,k≥2.
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  1. Cotangent partial-fraction expansion
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  • Past exam of the mathematics course of the University of Cambridge / 2008 / iii / Paper 33 / 2 / Solution

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