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Invariance of noise-whitened spectral angles to the whitening factor means that any two complete whitening transformations for the same positive-definite covariance give the same angles between transformed shapes. Suppose square invertible matrices satisfy $W_{i}C{W}_i^T=I$. Put $Q=W_2{W}_1^{-1}$. Since $C=W_1^{-1}{W}_1^{-T}$,Thus $Q$ is orthogonal. It may rotate or reflect the whitened coordinates, but preserves their inner products, norms and angles. The noise-whitened angle between spectral signal and nuisance shapes is consequently a property of the shapes and covariance, not a particular whitening algorithm.

For an original example, chooseDirect multiplication gives $W_{1}C{W}_1^T=I$. With $\mathbf{s}=(2,1{)}^T$ and $\mathbf{x}=(2,2{)}^T$, the whitened shapes are $(1,0{)}^T$ and $(1,1{)}^T$, meeting at $45^{\circ }$. Using $W_2=Q{W}_1$ instead gives $(0,1{)}^T$ and $(-1,1{)}^T$, again at $45^{\circ }$, although the coordinate components differ.

SciPy describes covariance whitening as transforming variables to unit covariance and illustrates it with a precision-matrix construction.^[ref] The matrix proof above establishes the invariance independently of an implementation's chosen factor.

The same principle requires covariance-consistent rescaling of whitened spectral coordinates. If raw measurement units change by an invertible matrix $D$, transform both shapes by $D$ and covariance by $C^{\prime }=DC{D}^T$; then $W^{\prime }=W_1{D}^{-1}$ reproduces the same whitened shapes. Changing a plotted channel's scale without transforming its noise model is not this invariant operation.

The claim assumes a full whitening of a positive-definite covariance. Truncating modes can remove information and change angles, while a singular covariance requires restriction to its supported range. Uncertainty in an estimated covariance is also separate from this exact algebraic invariance.

Noninvertible spectral compression versus a coordinate change distinguishes discarding spectral coordinates from expressing the same measurements in different units. The covariance-consistent rescaling of whitened spectral coordinates article assumes an invertible transformation. A compression $\mathbf{z}=B\mathbf{y}$ with fewer independent rows than input coordinates instead has covariance $C_z=BC{B}^T$ and may lose information even when this covariance is propagated correctly.^[ref]

For positive-definite $C$ and a known signal shape $\mathbf{s}$, compare the squared noise-weighted signal sizesassuming $B$ has independent rows. Put $\mathbf{t}=C^{-1/2}\mathbf{s}$ and $M=B{C}^{1/2}$. ThenThe matrix $P$ is an orthogonal projector. This proves that compression cannot increase this signal measure under the stated covariance model. The condition for preserving a spectral signal under linear compression is that its whitened shape lie entirely in the retained subspace.

For an original example, let $C=I_2$, desired shape $\mathbf{s}=(1,1{)}^T$ and nuisance shape $\mathbf{x}=(1,-1{)}^T$. Keeping only the first channel, $B=(1,0)$, reduces $J$ from two to one and makes both shapes the same scalar. An unknown nuisance amplitude can then imitate the desired signal exactly.

Summing instead, $B=(1,1)$, gives desired response two, nuisance response zero and noise variance two. It retains $J_B=2$ for this particular signal while rejecting that nuisance. Thus a noninvertible map can preserve a chosen estimation task, but cannot in general be reversed to recover every original spectral component.

The primary Raman apparatus records array spectra before subsequent spectral processing.^[ref] Choose compression against the scientific signal and nuisance model, and propagate the full covariance. Correct uncertainty accounting does not restore a spectral distinction removed by the map.