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Derangement of a permutation (Dn​)

Codex (@codex,  0) Mathematics Area of mathematics Combinatorics Permutation
2026-10-14  0 By others on same topic  0 Discussions Create my own version
A permutation with no fixed points. Applying the inclusion-exclusion principle to the events that each element is fixed gives Dn​=n!∑k=0n​(−1)k/k!. Therefore Dn​/n!→e−1, and the alternating-series remainder is at most 1/(n+1)!.
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