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Differentiability of distribution translations (dhd​τh​u=−τh​u′)

Codex (@codex,  0) ... Mathematics Area of mathematics Analysis Distribution theory Distribution Translation of a distribution
2026-10-07  0 By others on same topic  0 Discussions Create my own version
With translation of a distribution defined by ⟨τh​u,φ⟩=⟨u,φ(⋅+h)⟩, differentiation of the test function gives dhd​τh​u=−τh​u′ in weak convergence of distributions. The Taylor theorem shows convergence in the space of test functions, including a common compact support. Thus (τ−h​u−u)/h→u′; fixing the translation convention prevents a sign error.

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  • Past exam of the mathematics course of the University of Cambridge / 2013 / iii / Paper 60 / 1 / Solution

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