Solution

Past exam of the mathematics course of the University of Cambridge / 2007 / iii / Paper 10 / 5 / Solution

Past exam of the mathematics course of the University of Cambridge / 2007 / iii / Paper 1 / 2 / a / Solution

Past exam of the mathematics course of the University of Cambridge / 2007 / iii / Paper 1 / 2 / b / Solution

Past exam of the mathematics course of the University of Cambridge / 2007 / iii / Paper 1 / 2 / c / Solution

Past exam of the mathematics course of the University of Cambridge / 2007 / iii / Paper 19 / 2 / Solution

Past exam of the mathematics course of the University of Cambridge / 2007 / iii / Paper 44 / 1 / Solution

Past exam of the mathematics course of the University of Cambridge / 2007 / iii / Paper 6 / 1 / Solution

Past exam of the mathematics course of the University of Cambridge / 2007 / iii / Paper 6 / 4 / Solution

Past exam of the mathematics course of the University of Cambridge / 2007 / ii / Paper 4 / 19H / Solution

Past exam of the mathematics course of the University of Cambridge / 2008 / ib / Paper 4 / 11G / Solution

Past exam of the mathematics course of the University of Cambridge / 2008 / iii / Paper 4 / 2 / a / Solution

Past exam of the mathematics course of the University of Cambridge / 2008 / iii / Paper 4 / 3 / a / Solution

Past exam of the mathematics course of the University of Cambridge / 2008 / iii / Paper 7 / 2 / b / Solution

Past exam of the mathematics course of the University of Cambridge / 2009 / ia / Paper 1 / 6B / Solution

Past exam of the mathematics course of the University of Cambridge / 2009 / iii / Paper 4 / 2 / a / Solution

Past exam of the mathematics course of the University of Cambridge / 2009 / iii / Paper 4 / 2 / b / Solution

{title2=$\oplus$}
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= Direct sum of vector spaces
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The direct sum $U\oplus W$ of two <vector space>[vector spaces] consists of pairs $(u,w)$ with componentwise operations. A vector space is an internal direct sum of subspaces $U$ and $W$ exactly when every vector has a unique expression $u+w$ with $u\in U$ and $w\in W$.

Direct sum

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 Incoming links: Direct sum