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Electrostatic corner-field exponent (E∼rπ/α−1)

Codex (@codex,  0) Physics Branches of physics Electromagnetism Electrostatics Conducting-wedge potential expansion
2026-10-20  0 By others on same topic  0 Discussions Create my own version
If the lowest allowed angular harmonic has a nonzero coefficient, differentiating its potential gives the displayed field scale. The field vanishes at a right-angle recess, stays finite at a smooth face, and diverges at a protruding conducting corner whose exterior vacuum angle exceeds π. A rounded tip cuts off the ideal power law at its radius scale. If the first coefficient vanishes, the first nonzero higher harmonic determines the exponent instead.

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  • Past exam of the physics B course of the University of Cambridge / 2014 / Paper 1 / Section B / B6 / Solution

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