Entropy bound for a Hamming ball (${\sum }_{j\le \rho n}\left(\genfrac{}{}{0ex}{}{n}{j}\right)\le e^{nh(\rho )}$)

For $0<\rho \le 1/2$, the number of binary words within Hamming distance $\rho n$ of a fixed word is at most $e^{nh(\rho )}$, with the binary entropy function in natural logarithms. In $1={\sum }_j\left(\genfrac{}{}{0ex}{}{n}{j}\right){\rho }^j(1-\rho {)}^{n-j}$, each summand weight for $j\le \rho n$ is at least ${\rho }^{\rho n}(1-\rho {)}^{n(1-\rho )}=e^{-nh(\rho )}$. Also $h^{\prime \prime }(\rho )=-1/(\rho (1-\rho ))\le -4$, so $\log 2-h(1/2-a)\ge 2a^2$. These two bounds give the approximate-recovery denominator in the list-decoding Fano inequality.