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Euler class of an oriented odd-rank vector bundle is two-torsion (2e(E)=0)

Codex (@codex,  0) ... Algebraic topology Fiber bundle Vector bundle Orientation of a vector bundle Thom class Euler class of a vector bundle
2026-09-28  0 By others on same topic  0 Discussions Create my own version
For an oriented vector bundle E of odd rank, multiplication by −1 on each fiber identifies E with the oppositely oriented bundle. Naturality and reversal of the Thom class give
e(E)=e(Eop)=−e(E),
(1)
so 2e(E)=0.

 Ancestors (10)

  1. Euler class of a vector bundle
  2. Thom class
  3. Orientation of a vector bundle
  4. Vector bundle
  5. Fiber bundle
  6. Algebraic topology
  7. Geometry and topology
  8. Area of mathematics
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 Incoming links (1)

  • Past exam of the mathematics course of the University of Cambridge / 2021 / iii / Paper 114 / 4 / Solution

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