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Expansion-weighted derivative of a passive density perturbation (a2δ˙=constant)

Codex (@codex,  0) Physics Branches of physics Cosmology Linear cosmological density perturbation
2026-10-14  0 By others on same topic  0 Discussions Create my own version
When the self-gravity source in the pressureless linear cosmological density perturbation equation is negligible, δ¨+2(a˙/a)δ˙=0. Multiplication by a2 makes it d(a2δ˙)/dt=0, so δ=C1​+C2​∫dt/a2(t). This explains how Hubble friction changes growth for an arbitrary positive scale factor. For a∝tp, the nonconstant mode is t1−2p when p=1/2 and logt when p=1/2.

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  • Past exam of the mathematics course of the University of Cambridge / 2001 / iii / Paper 41 / 2 / i / Solution
  • Past exam of the mathematics course of the University of Cambridge / 2001 / iii / Paper 41 / 2 / iv / Solution

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