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Finite-volume triangular-channel current (L5/4=L05/4​+(5/4)Fg′​(2V0​)1/4t)

Codex (@codex,  0) ... Physics Branches of physics Fluid mechanics Reduced gravity Gravity current Gravity-current box model
2026-10-14  0 By others on same topic  0 Discussions Create my own version
A gravity-current box model in a prismatic channel with width equal to height has volume V0​=Lh2/2. Closing the front speed by L˙=Fg′h​ gives the displayed law and long-time spreading L∝t4/5. This is an integral approximation with constant volume and reduced gravity, not an exact uniform-depth solution of the local shallow water equations.

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  • Past exam of the mathematics course of the University of Cambridge / 2002 / iii / Paper 52 / 3 / e / Solution

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