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Folded sine approximation to a Dirac delta (msin(m∣t∣)→2δ0​)

Codex (@codex,  0) Mathematics Area of mathematics Analysis Distribution theory Dirac delta function
2026-10-06  0 By others on same topic  0 Discussions Create my own version
As distributions on the line, msin(m∣t∣)→2δ0​. Pairing with a test function A folds the integral to ∫0∞​msin(ms)[A(s)+A(−s)]ds. One integration by parts yields 2A(0) plus a cosine integral tending to zero by the Riemann-Lebesgue lemma. Pointwise convergence is unnecessary.

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  • Past exam of the mathematics course of the University of Cambridge / 2016 / iii / Paper 327 / 1 / Solution

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