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If $V_{\kappa }\models \mathrm{ZFC}$, it has the standard natural numbers and standard finite proofs. Every arithmetical sentence, including a formal consistency statement, therefore has the same truth value in $V_{\kappa }$ and the universe.

Gentzen's consistency argument associates finite arithmetic derivations with effective ordinal notations below epsilon zero. An alleged contradiction admits an effective proof reduction preserving the contradictory end-sequent and strictly decreasing the assigned ordinal. Termination would therefore produce a normal contradiction, excluded by inspection of the logical rules and true atomic axioms. This explains why the relevant transfinite induction principle implies formal consistency statement. For a finite slow-well-ordering formulation one additionally needs the controlled-termination miniaturization theorem, rather than assuming that ordinary proof reductions have linearly growing size. The reduction program is discussed in math.stanford.edu/~feferman/papers/reductive.pdf .

Starting from a recursively axiomatized arithmetic first-order theory $T_0$ with the usual arithmetical provability predicates, defineIf every stage is first-order consistent, the Gödel second incompleteness theorem makes every step strict in the consistency-strength preorder: the next stage proves the preceding stage's formal consistency statement, which that preceding stage cannot prove. Every formal proof from the effective union $T_{\omega }={\bigcup }_{n<\omega }{T}_n$ uses only finitely many axioms and lies in one stage. Thus the union is first-order consistent under this hypothesis and lies strictly above every finite stage. Arithmetic soundness of $T_0$ is a sufficient starting assumption, since each added formal consistency statement is then true in the standard natural numbers.

Consistency of $T_0$ alone does not ensure consistency of the next stage. Assuming Peano arithmetic is first-order consistent, $T_0=\mathrm{PA}+\neg \mathrm{Con}(\mathrm{PA})$ is first-order consistent by the Gödel second incompleteness theorem. Proof inclusion makes it prove $\neg \mathrm{Con}(T_0)$, so adding $\mathrm{Con}(T_0)$ produces an inconsistent next stage. The hypotheses for a progression must therefore distinguish a consistent starting theory from consistency of all its iterates.

Assume $S⊢\neg X$ and $S⊢BX\to X$. Combining these theorems gives $S⊢\neg BX$. Because $X$ is refutable, $\neg BX$ is a legitimate formal consistency statement for $S$: the standard contradiction first-order sentence and $X$ are provably interderivable, and the derivability conditions transfer those implications to their provability statements.

Thus if $S$ were consistent, the Gödel second incompleteness theorem would contradict $S⊢\neg BX$. Consequently the assumed reflection theorem forces $S$ to be inconsistent; explosion then gives $S⊢X$. This establishes the instance of Löb's theoremfor every $X$ refutable in $S$, using only the second incompleteness theorem.

The Gödel second incompleteness theorem says that a consistent, effectively axiomatized first-order theory with enough arithmetic and its standard derivability and diagonalization properties cannot prove its formal consistency statement ${\mathrm{Con}}_S=\neg B\perp$.

If a consistent $S$ proved ${\mathrm{Con}}_S$, it would prove $B\perp \to \perp$ by classical propositional logic. Apply Löb's theorem to $A=\perp$. This would give $S⊢\perp$, contradicting consistency. ThereforeFor an inconsistent first-order theory the conclusion need not hold, since it proves every first-order sentence.

Use the preceding fixed point with $q=\perp$. If the chosen arithmetic interpretation sends $\perp$ to a PA-refutable sentence $Z$, it gives the arithmetic sentenceThis follows from Arithmetical soundness of GL. Since Peano arithmetic proves $\neg Z$, the two implications are equivalent to negated provability:Thus $C$ expresses the formal consistency statement for Peano arithmetic and is also a negative provability fixed point, like its Gödel sentence $G$.

Apply the supplied modal uniqueness formula to the context with a modalized occurrence $X(p)=(\square p\to \perp )$, with two fresh variables interpreted as $G$ and $C$. A modalized occurrence means that each indicated variable occurrence lies inside a box. Peano arithmetic proves both arithmetic fixed-point equations. The first derivability condition boxes those equations, so the translated uniqueness formula givesOne must not infer $G\leftrightarrow C$ by reflection. Instead, distribution and the provability of the two propositional projections give $\mathrm{PA}⊢BG\leftrightarrow BC$. Negating and using the two fixed-point equations now yieldsThis proves the Equivalence of a Gödel sentence and a consistency statement using the required modal soundness, fixed point and uniqueness results.

The consistency implication needs more than the fact that the finite tree statement is unprovable in Peano arithmetic. Its mechanism is a concrete encoding of ordinal descent by bad finite-tree sequences, combined with the controlled-termination form of Gentzen ordinal reduction for arithmetic.

First define the natural-sum ordinal rank of a finite rooted tree. A leaf has rank zero, and a tree with immediate child subtrees $T_1,\dots ,T_m$ haswhere $\#$ is Hessenberg natural sum. By induction every such rank is below epsilon zero. Conversely, if $\alpha ={\sum }_{j=1}^r{\omega }^{{\alpha }_j}{c}_j$ is in Cantor normal form, represent it by a root with $c_j$ copies of the recursively constructed tree for ${\alpha }_j$. The leaf represents zero. Denote the resulting canonical tree by $\tau (\alpha )$ and its vertex count by $\Vert \alpha \Vert$.

We claim that a rooted-tree homeomorphic embedding $T⪯U$ implies $o(T)\le o(U)$. If the roots match, the source child subtrees embed into distinct target branches. By induction their ranks do not decrease; exponentiation and Hessenberg natural sum preserve these comparisons, and additional target branches only increase the sum. If the source root maps below the host root, its entire image lies in an immediate subtree $V$ of $U$. Induction gives $o(T)\le o(V)$, whileThis also holds when $o(V)=0$. Thus the claim follows by induction on the host tree. In particular,

Consequently Friedman's finite form of Kruskal's theorem supplies slow well-ordering below epsilon zero: for each $k$, descending ordinal sequences with $\Vert {\alpha }_i\Vert \le k+i$ have uniformly bounded length. Otherwise their canonical trees would be arbitrarily long admissible bad sequences. The notation system and its comparisons are primitive recursive, and there are only finitely many notations of bounded norm.

The proof-theoretic input is the following precise miniaturization lemma: for the standard effective Cantor normal form notation system below ${\epsilon }_0$, slow well-ordering with linear norm control implies the formal consistency statement for Peano arithmetic. The Friedman–Smith controlled-termination theorem, stated in its general ordinal-analysis form in Section 2.2 of formal.hknu.ac.kr/Publi/kruskalJKMS.pdf , supplies this implication over arithmetical comprehension theory ${\mathrm{ACA}}_0$, whose first-order part is conservative over Peano arithmetic. This is an established proof-theoretic lemma, separate from the elementary tree-rank calculation above.

Here is why that lemma is a consistency result. Gentzen ordinal reduction for arithmetic assigns an alleged arithmetic contradiction an effective ordinal below ${\epsilon }_0$. Reducing cuts and induction inferences preserves the contradictory end-sequent while strictly decreasing the assigned ordinal. A terminal normal derivation of a contradiction is excluded by inspection of the rules. The miniaturization argument converts this reduction/induction analysis into finite controlled descents: a contradictory proof would yield arbitrarily long descending notation sequences with a common initial allowance and linear norm control. Slow well-ordering excludes these. The control conversion is substantive; ordinary proof reductions must not simply be asserted to have linear-size growth. Gentzen's ordinal-reduction framework is discussed in math.stanford.edu/~feferman/papers/reductive.pdf .

Combining the coding with that precise termination lemma givesThus the finite combinatorial principle proves that no PA proof of a contradiction exists in the specified arithmetic metatheory. If consistent Peano arithmetic proved FFF, it would also prove its own formal consistency statement: the displayed implication is arithmetical and the first-order conservativity of ${\mathrm{ACA}}_0$ transfers it to PA. This contradicts the Gödel second incompleteness theorem. It is the consistency implication, rather than unprovability by itself, that explains the strength of the finite tree principle.

For a first-order theory $R$ extending ZFC, let $C_R$ be its set of formal consequences and let $\mathrm{Cons}$ denote the class of formal consistency statements $\mathrm{Con}(Q)$ for recursively axiomatized extensions $Q$ of ZFC. Using Gödel numbering to code proofs and theories, these objects and the following comparison are definable in the base theory ZFC.

The consistency-strength preorder isThus every consistency assertion provable in $T$ is also provable in $S$. Its strict part is

Let $\mathrm{IC}$ be the sentence asserting that a strongly inaccessible cardinal exists, and begin withDefine the iterated consistency progressionThe construction is effective, so every $T_n$ and $T_{\infty }$ is a recursively axiomatized first-order theory extending ZFC.

Because $T_{n+1}$ extends $T_n$, every theorem of $T_n$, including every formal consistency statement it proves, is a theorem of $T_{n+1}$; hence $T_n{\le }_{\mathrm{Cons}}{T}_{n+1}$. The theory $T_{n+1}$ proves $\mathrm{Con}(T_n)$ by construction, whereas a consistent $T_n$ cannot prove its own consistency by Gödel second incompleteness theorem. ThereforeLikewise $T_{\infty }$ extends every $T_n$ and contains $\mathrm{Con}(T_n)$ as an axiom already at stage $n+1$, while $T_n$ does not prove it. Consequentlyassuming the stated consistency hypotheses.

Abbreviate $P(┌A┐)$ by $\square A$. Since $S⊢\neg X$, it proves $X\to G$. The theoremhood and distribution conditions giveThe fixed-point equation gives $S⊢G\to (\square G\to X)$, because $G$ implies $\neg \square G$ and a false antecedent implies any conclusion. Applying theoremhood and distribution yieldsPositive introspection gives $\square G\to \square \square G$; distribution then gives $\square G\to \square X$. Thus $S⊢\square G\leftrightarrow \square X$. Combining with $G\leftrightarrow \neg \square G$ provesIn particular, choosing a fixed logical contradiction for $X$ identifies this Gödel sentence with the formal consistency statement of $S$.

Gödel's second incompleteness theorem says that a consistent effectively presented arithmetic theory with an adequate proof predicate cannot prove its formal consistency statement. The background strength must support the diagonal lemma and the derivability conditions, as in the present arithmetic setting.

Löb's theorem saysIt is a theorem about derivability for every sentence $A$, not merely an external soundness assertion about the interpretation of $\square$. Taking $A=\perp$, a proof of consistency gives $S⊢\square \perp \to \perp$; Löb then gives $S⊢\perp$. Thus a consistent $S$ cannot prove consistency. This is how the second incompleteness theorem is the contradiction-sentence instance of Löb's more general result.

Primitive recursive arithmetic formalizes primitive recursive functions, their defining equations, and quantifier-free induction. It is a weak arithmetic base for coding finite syntax and checking effective proof reductions. Assertions that a combinatorial principle implies formal consistency statement must specify such a base or another arithmetic metatheory.

Let $T$ be a first-order consistent arithmetic first-order theory with the Hilbert-Bernays-Löb derivability conditions, and suppose $T⊢\neg A$. Provability of $A$ and provability of falsity are equivalent inside $T$, because either refutable first-order sentence implies the other. Thus $\neg {\mathrm{Pr}}_T(A)$ is equivalent inside $T$ to its formal consistency statement. The second incompleteness theorem gives $T⊬\neg {\mathrm{Pr}}_T(A)$.

Use the unary Cantor normal form tree norm, counting one root and recursively counting all repeated exponent subterms. There are only finitely many notations of bounded norm. This finite principle bounds all descending sequences whose norms grow at most linearly with the position. Friedman's finite form of Kruskal's theorem implies it through the natural-sum ordinal rank of a finite rooted tree. The Friedman–Smith miniaturization theorem turns this controlled termination principle for standard epsilon-zero notations into the formal consistency statement for Peano arithmetic; the technical ordinal-analysis result is needed in addition to the tree coding. Section 2.2 of formal.hknu.ac.kr/Publi/kruskalJKMS.pdf records the general miniaturization and soundness theorem.