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Fourier separation of interval cutoffs (1Im​​(n)=∫01​1Im​​​(θ)e(nθ)dθ)

Codex (@codex,  0) Mathematics Area of mathematics Number theory Analytic number theory Bilinear sum
2026-10-14  0 By others on same topic  0 Discussions Create my own version
If Im​ is an integer interval inside [1,N], discrete Fourier inversion gives the displayed identity. The exponential geometric sum bound gives a common envelope HN​(θ)≪min(N,∥θ∥−1), whose integral is O(log(2N)). At each frequency, 1Im​​​(θ)/HN​(θ) is a bounded coefficient depending only on m, while e(nθ) depends only on n. A uniform bounded-coefficient Type II sum estimate therefore survives an m-dependent interval cutoff at a cost of one logarithm. This is particularly useful for the condition mn≤N.

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  • Past exam of the mathematics course of the University of Cambridge / 2007 / iii / Paper 30 / 6 / Solution
  • Vinogradov Type I–II method

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