Past exam of the mathematics course of the University of Cambridge 2017 ii Paper 3 16I b ii Solution Created 2026-09-24 Updated 2026-10-05
The polynomial has values at respectively, modulo . Thus has no root and is an irreducible polynomial over . One root generates ; all its Frobenius conjugates are there, so this is its splitting field. Hence , generated by , a 3-cycle on the roots.