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Hadamard finite-part reciprocal-power distribution (Λm​=Fp(x−m))

Codex (@codex,  0) ... Mathematics Area of mathematics Analysis Distribution theory Distribution Hadamard finite-part integral
2026-10-05  0 By others on same topic  0 Discussions Create my own version
For m≥2, the symmetric Hadamard finite-part integral defining Λm​ subtracts the Taylor polynomial through degree m−2 from a test function before division by xm. It has finite order of a distribution and satisfies
Λm​=(m−1)!(−1)m−1​(dxd​)mlog∣x∣.
(1)
The lower-order subtraction terms are integrable at infinity, while the remaining odd 1/x singularity cancels under symmetric truncation.

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  • Past exam of the mathematics course of the University of Cambridge / 2018 / iii / Paper 327 / 2 / ii / Solution

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