Past exam of the mathematics course of the year 2 of the natural sciences course of the University of Cambridge 2003 Paper 1 9 Solution Created 2026-10-18 Updated 2026-10-20
Vary by with . The first variation of the functional isThe boundary term from integration by parts is zero. The fundamental lemma of the calculus of variations therefore gives . For , independently vary and with zero endpoint variations; the two Euler-Lagrange equations areFor the optical path, Fermat principle makes stationary. In cylindrical coordinates its integrand is , with . There is no explicit dependence. The Beltrami identity for several dependent variables givesThe conserved quantity is the axial component of the optical momentum of a ray. As , squaring and inverting yieldsNow suppose and seek a path of radius . The angle is a cyclic coordinate, so is conserved. At fixed radius this is strictly increasing in , forcing constant. The radial Euler-Lagrange equation reduces toConsequently the helical rays in a radially graded refractive index haveA real nonzero helix exists at such a radius when , and its helical pitch is . If , the solution is instead a straight axial light ray. Thus radial dependence permits constant-radius rays for suitable profiles; an arbitrary radial profile need not support a nonzero real helix. This qualification is necessary, for example when the refractive index increases with radius.